Dark Injector

Title	Author	Created	Published	Tags
Dark Injector	Jon Marien	March 17, 2025	March 17, 2025	[[#ctfs|#ctfs]], [[#writeups|#writeups]], [[#tryhackme|#tryhackme]]

Dark Injector Solution

Opening up the VM, I immediately browsed to /tmp/ and listed the files within it. I checked the hidden files, with ls -la, and I found a text file which contained information concerning the public key! I used Claude 3.7 Sonnet to factor the n value I found: I then used this simple script to calculate the private key of RSA:

#!/usr/bin/env python3
 
# The known public key components
n = 34028236692093846084393694896501188881
e = 65537
 
# After factoring n, enter the values of p and q
p = 5842673006673423723 # First prime factor you found
q = 5824603262460268301 # Second prime factor you found
 
# Calculate totient: φ(n) = (p-1)(q-1)
phi = (p - 1) * (q - 1)
 
# Calculate d (private exponent): d ≡ e^(-1) (mod φ(n))
# In Python 3.8+:
d = pow(e, -1, phi)
# For older Python:
# from sympy import mod_inverse
# d = mod_inverse(e, phi)
 
print(f"Private exponent (d): {d}")
 

Now, we know d is 7587021479694414575537988236040711273.

RSA_Key.py:

AES_Decrypt.py